# Tricky concepts of Operators in C Programming Language

We assume that you know the basics of C Programming.

1.
int c=10,a=5,d;
d=a=c;
After the execution of above statement d will have the value 10.

Explanation: Equality operator associates Right to Left, i.e. in the above statement first c is assigned to a.
The  expression a=c evaluates to the value of a after the assignment takes place. Then this value is assigned to d.

2.
int x=2;
x*=3+2;
After the execution of above statement x will have the value 10.

Explanation: Right Expression is evaluated first & then the result is multiplied to the left variable. Also note that "+" operator has higher precedence over "*=" operator.

3.
x*=y=z=4;
if x was initially 10, then after execution of the above statement x=40, y=4 and z=4

4.
x=y==z;
if y & z have same values, (i.e. if y=4, and z=4), then y==z will return the value 1, which will be stored in x. If y is not equal to z, (i.e. if y=5, and z=4), then y==z will return the value 0 which will be stored in x.

5.
x=1; z=0;
z=x++ - 1;
The above statement will make value of z=0 & x=2.

Explanation: When increment operator (i.e. ++) is used as a postfix then the statement is evaluated first & then the variable will be incremented. When increment operator (i.e. ++) is used as a prefix then the variable will be incremented first & then the statement will be evaluated.

6.
int i=3,j;
j=++i * ++i * ++i;
When executed we will get i=6 and j=216.

Explanation: The value of i is used after it is incremented thrice.  Therefore j=6*6*6=216.

7.
int i=3,j;
j=i++ * i++ * i++;
When executed we will get i=6 and j=27.

Explanation: The value of i is incremented only after the execution of the statement is over.  Therefore j=3*3*3=27.

8.
int x=8;
x-=--x - x--;
After execution x will be 6.
Hint: Evaluate right side first.

9.
x=3; y=2; z=1;
printf("%d",x<y ? x++ : y++);
We know that since condition is false y++ will be evaluated. On execution, the above statement will print 2. Only after printing the value of y will be incremented.

10.
x=3; y=3; z=1;
printf("%d",z+=x<y ? x++ : y++);
On execution, the above statement will print 4. Only after printing the value of y will be incremented.

11.
i = (j++, k++);
Here, the comma operator is used to execute three expressions in one line: assign k to i, increment j, and increment k. The value that i receives is always the rightmost expression. if i=0, j=10, k=20 initially, after execution: i=20, j=11, k=21;

#### 1 comment:

1. Many languages (eg C) and determining the distinguished instruction. The difference is that the instruction executes the code and the definition creates an identifier (that is, can be regarded as the definition of assignment statement).